Problem: \(F_1 = 2\,\text{kN}\) has \(\theta = 120^\circ\) in the \(xy\) plane and \(\phi = 60^\circ\) from \(+z\). \(F_2 = 3\,\text{kN}\) has \(\theta_x = 120^\circ\), \(\theta_y = 60^\circ\), \(\theta_z = 45^\circ\). A third force \(\mathbf{F}_3\) is added so that the resultant of all three becomes \(\{1.2\,\mathbf{k}\}\,\text{kN}\). Find \(\mathbf{F}_3\), its magnitude and its direction angles.

Third Force for a Vertical Resultant in 3D
ID: h9rlraa4cf



























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